(x^2-5)*4-7/3+6=9

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Solution for (x^2-5)*4-7/3+6=9 equation: 


x in (-oo:+oo)

4*(x^2-5)-(7/3)+6 = 9 // - 9

4*(x^2-5)-(7/3)-9+6 = 0

4*(x^2-5)-7/3-9+6 = 0

(3*4*(x^2-5))/3-7/3+(-9*3)/3+(3*6)/3 = 0

3*4*(x^2-5)-9*3+3*6-7 = 0

12*x^2-67-27+18 = 0

12*x^2-94+18 = 0

12*x^2-76 = 0

(12*x^2-76)/3 = 0

(12*x^2-76)/3 = 0 // * 3

12*x^2-76 = 0

12*x^2 = 76 // : 12

x^2 = 19/3

x^2 = 19/3 // ^ 1/2

abs(x) = (19/3)^(1/2)

x = (19/3)^(1/2) or x = -(19/3)^(1/2)

x in { (19/3)^(1/2), -(19/3)^(1/2) }

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